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- Lens equation is derived by using Fermat"s principle. 用费马原理推导了透镜的物像公式.
- Generation Fermat's principle into left handed materials[J]. 引用该论文 谭康伯;梁昌洪;安翔.
- Lutheran establishment in 1943, freedom, Euler Township 3. 1943年设立信义、自由、欧拉3个乡。
- The numerical solution of Euler equations is provided as flowsolver. 翼型的流场解由欧拉方程的数值解提供。
- Just how Fermat's ideas on coordinate geomitry evolved is not known. Fermat的坐标几何究竟是怎样产生的,我们尚不知道。
- Gimbal lock is a phenomenon that easily affects Euler angle representations. 万向节锁是一种容易影响到欧拉角表现的现象。
- Just how Fermat's ideas on coordinate geometry evolved is not known. Fermat的坐标几何究竟是怎样产生的,我们尚不知道。
- As well as Pythagoras theorem and Fermat's last theorem summarizes the total. 也是对毕达哥拉斯定理和费尔马最后定理的总概括。
- In 1728 Euler gave differential equations for geodesics on surfaces. 1728年,奥伊勒绘出了曲面上测地线的微方程。
- We obtain an analogue of Euler formula by using the method of moving frames. 利用活动标架法,得出了一个类似的欧拉公式。
- First, the relation between Boltzmann and Euler equations is analyzed. 然后,利用一种特殊的插值技术构造了一类高分辨波尔兹曼型差分格式。
- The cost model based on Euler Histogram isthe focal point of the dissertation. 基于欧拉直方图估算查询结果集大小的代价模型是论文研究的重点。
- Quaternion can avoid gibbs lock if you use euler angle to rotate 3d model. 四元数可避免吉布斯锁如果您使用的欧拉角旋转三维模型。
- French mathematician and philosopher; invented an adding machine; contributed (with Fermat) to the theory of probability (1623-1662). 法国数学家和哲学家(1623-1662);发明了一种加法机;(和弗麦特一起)对概率理论做出了贡献。
- Join the project discussion forum or an independent discussion forum about Fermat numbers. 加入项目论坛或关于费马数的独立论坛。
- We shall deduce the result from a lemma about Euler trails in directed multigraphs. 我们用一个关于有向重图中尤拉迹的引理来证明这个定理。
- Based on Fermat's principle, the equation satisfied by light path in gradient refraction index medium is derived. 摘要文章以费马原理为基础,推导了一维渐变折射率介质中光线方程满足的微分方程;
- Euler's spirit for philosophic disputes remained undampen and he continued to engage in them. 争论哲学的精神仍常盛不衰,他持续地致力于此。
- Probability theory began, with Pascal and Fermat (1654), as a theory of games of chance, i.e. 世上的许多事确可通过个人的不断努力奋斗而做到、而改变。
- Thurs, since there are infinitely many Fermat numbers, there must be infinitely many primes. 所以,因为有无穷个费马数,所有必定有无穷个质数。