设字节长度为b位,该代码的校验部分长度为m字节,信息部分长度为k字节,则最大代码长度为n=2~(m-2)(2~(b-1)+1)字节。

• If the byte length is b, the length of checking part of the code is m bytes, the length of information part of the code is k bytes, then the maximal code length will be n=m+k=2m-2 (2b-1+1) bytes.